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I felt like the (∞,1) section should give an abstract description rather than a model specific one, so I’ve done so, and proved in the abstract the equivalence between the hom-space and slice-category characterizations.
It feels like cheating to invoke the Grothendieck construction for it; can the argument be made just as cleanly without it?
… I’m having trouble with the formatting, so I’m going to do some bisection to track down the issue….
It’s weird that you can’t do tikzcd inbetween dollar-sign pairs, and you have to actually use the centre environment thing.
Thanks for the additions.
Yes, the tikzcd
-functionality is not part of Instiki (which is the software platform the Lab rendering engine is using) but is an external add-on that Richard kindly added a while back, so that we can have decent diagram typesetting at all.
My understanding is that there are plans to improve on this and other aspects, but I gather the priority right now is to get the Lab migrated from its server at CMU (which is running out) to a cloud provider.
As usual, if anyone is interested in lending Richard a hand with coding desired functionality for the Lab, drop him a note and he may tell you what you could do!
Correction: a Cartesian morphism is the special case of a strictly final lift of a structured sink when the sink is a singleton.
Removed an old discussion:
David Roberts: There would surely be an anafunctor version of this, that would require no choices whatsoever. It is unlikely that I would be able to find time to write this up, so my plea goes out to those in the know…
I imagine that there would then be an -version using whatever passes as anafunctors in that setting (dratted memory, failing at the first gate)
Mike Shulman: Yes, there would surely be such a version. (-: The simplest way would be to take the specifications for the anafunctor to be the cartesian morphisms over , with domain and codomain giving the functions and . Unique factorization would give you the values of morphisms.
David Roberts: just stumbled on this old comment - I’m reading Makkai more closely, and I’m convinced that basically anything defined by a universal property is given by a saturated anafunctor. So this is a heads up for posterity, that a map is a fibration iff the fairly obvious span of functors defines a saturated anafunctor.
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