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    • CommentRowNumber1.
    • CommentAuthorAndrew Stacey
    • CommentTimeDec 16th 2011

    This was posted on the “container” Mathforge forum. I left a message saying that it should be reposted here and that I would delete it after a few days. It hasn’t been reposted here, but I’m going to delete it now so I’m recording it here for posterity. Although we can use this as a guide to making some things clearer on the nLab (which I believe that Urs has already done), there’s no point in trying to respond here until the questioner turns up.

    a naive question ?

    This is about the notion of “smooth path”, which is fundamental for holonomy.

    Does that mean that it admits a smooth parametrizing ? I mean infintely derivable ? If so, I do not understantd how it could admit “sitting instants” because I naively believe that it a smooth function has all derivatives zero, or is zero on an open set, it should be zero everywhere.

    I am sure I am wrong somewhere, but where ?

    many thanks

    (a second question It is clear for me that holonomy compose by group product for smooth spaces. But it seems that it does not for non smooth ones : if there is a discontinuity of the derivative at the joining point, one has to add a corresponding element of the group (corresponding to the rotation at that point). Am I right ?)

    • CommentRowNumber2.
    • CommentAuthorUrs
    • CommentTimeDec 16th 2011

    Just for the record: we have dealt with that here.