Want to take part in these discussions? Sign in if you have an account, or apply for one below
Vanilla 1.1.10 is a product of Lussumo. More Information: Documentation, Community Support.
I created a seperate Kan object which was desribed in internal infinity-groupoid before. The combinatoric part in the motivation is not needed, yet.
What does “where sSet is regarded as a Set-enriched category” mean? It hardly seems necessary…
Also, I don’t understand the third equivalent condition for X to be Kan. What is Δk[n]? Can you spell it out more? I didn’t know there was any way to define a Kan complex in terms of some map being a bijection.
What does “where sSet is regarded as a Set-enriched category” mean? It hardly seems necessary…
Yes, this is not necessary. I wrote it this way to motivate the generalization.
Also, I don’t understand the third equivalent condition for X to be Kan. What is Δk[n]? Can you spell it out more? I didn’t know there was any way to define a Kan complex in terms of some map being a bijection.
I’ m sorry, there I did not type what I meant: the correct condition would be
”[Δ[n],X]d→Kn:={(x0,...,xk−1,xk+1,...,xn|dixj=dj−1xi,i¬=k,j¬=k,i<j} is an epimorphism ( [Λk[n],X] is then in bijection with Kn where di denotes the i-th face map and d:=d0×...×dk1×dk+1×...×dn). ”
So this condition is just a combinatoric description of [Λkn,X]. The intention behind this is to think of the horn as a collection of n consecutive (n-1)-simplices which the Kan condition then closes by adding a further (n-1)-cell.
I deleted this condition since it is not used in the generalization.
Maybe one could add some hints to conditions making a Kan objecct an internal ∞-groupoid. The nlab is down at the moment, so I can’t look up what there already stands in regard to this. Maybe one can use some description of objects of composable n-cells -someting like ×0≤i≤ns,t[Δ[n],X] where s:=dn⋆dn−1⋆dn−4⋆... and t:=dn−1⋆n−3⋆dn−5 are the pasting of degeneracies- too.
(Obviously something is wrong with the formatting)
Okay, I see; thanks!
1 to 5 of 5