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1. • CommentRowNumber1.
   • CommentAuthorMirco Richter
   • CommentTimeFeb 25th 2012
   • (edited Feb 25th 2012)
   • PermaLink
   Author: Mirco Richter
   Format: MarkdownItexIn http://ncatlab.org/nlab/show/Lie+2-algebra, at "... the differential respects the brackets: for all $ x \in g_0 $ and $h \in g_1$ we have $$ \delta [x,h]=[x,\delta h] $$ ..." is wrong. The equation should be: $$\delta \alpha(x,h) = [x,\delta h]$$ Since I don't know if I have the right to change an nLab entry,I post this here as an suggestion.

   In

   http://ncatlab.org/nlab/show/Lie+2-algebra, at

   “… the differential respects the brackets: for all $x \in g_0$ and $h \in g_1$ we have

   $$\delta [x,h]=[x,\delta h]$$

   …”

   is wrong. The equation should be:

   $$\delta \alpha(x,h) = [x,\delta h]$$

   Since I don’t know if I have the right to change an nLab entry,I post this here as an suggestion.

2. • CommentRowNumber2.
   • CommentAuthorDavid_Corfield
   • CommentTimeFeb 25th 2012
   • PermaLink
   Author: David_Corfield
   Format: MarkdownItexChange away. Everyone has the right. For a typo, no need to comment here. For a substantial change, leave a note at the forum.

   Change away. Everyone has the right. For a typo, no need to comment here. For a substantial change, leave a note at the forum.

3. • CommentRowNumber3.
   • CommentAuthorMirco Richter
   • CommentTimeFeb 25th 2012
   • PermaLink
   Author: Mirco Richter
   Format: Textdone

   done
4. • CommentRowNumber4.
   • CommentAuthorjim_stasheff
   • CommentTimeFeb 26th 2012
   • PermaLink
   Author: jim_stasheff
   Format: Text@ "... the differential respects the brackets: for all x∈g 0 and h∈g 1 we have δ[x,h]=[x,δh] ..." is wrong. The equation should be: δα(x,h)=[x,δh] yes and no 1. it is common to denote $\alpha$ as [ , ] 2. in the context of respecting the brackets, it might be better to write δ[x,h]= [δx,h]\pm [x,δh] and then remark for h in ...

   @
   
   "...
   the differential respects the brackets: for all
   x∈g 0 and
   h∈g 1 we have
   
   
   δ[x,h]=[x,δh]
   
   ..."
   
   is wrong. The equation should be:
   
   
   δα(x,h)=[x,δh]
   
   yes and no
   1. it is common to denote $\alpha$ as [ , ]
   2. in the context of respecting the brackets, it might be better to write
   
   δ[x,h]= [δx,h]\pm [x,δh]
   and then remark for h in ...
5. • CommentRowNumber5.
   • CommentAuthorMirco Richter
   • CommentTimeFeb 28th 2012
   • PermaLink
   Author: Mirco Richter
   Format: TextI agree on that, because the last equation is closer to the many bracket stuff of $L_\infty$-algebras. But then the definition in the nLab entry must be changed (or another definition must be added), because in the entry as it is there is no defined bracket $[.,.]$ for elements of degree zero and one.

   I agree on that, because the last equation is closer to the many bracket stuff of $L_\infty$-algebras.
   
   But then the definition in the nLab entry must be changed (or another definition must be added), because in the entry as it is there is no defined bracket $[.,.]$ for elements of degree zero and one.
6. • CommentRowNumber6.
   • CommentAuthorUrs
   • CommentTimeFeb 28th 2012
   • PermaLink
   Author: Urs
   Format: MarkdownItex> there is no Now there is.

   there is no

   Now there is.

7. • CommentRowNumber7.
   • CommentAuthorMirco Richter
   • CommentTimeFeb 28th 2012
   • (edited Feb 28th 2012)
   • PermaLink
   Author: Mirco Richter
   Format: MarkdownItex...

   …