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• CommentRowNumber1.
• CommentAuthorUrs
• CommentTimeJul 10th 2012

created conjugacy class

• CommentRowNumber2.
• CommentAuthorTobyBartels
• CommentTimeJul 11th 2012

I don’t have time to edit things now, but the example is wrong.

• CommentRowNumber3.
• CommentAuthorUrs
• CommentTimeJul 11th 2012

Sorry. Fixed. Thanks.

• CommentRowNumber4.
• CommentAuthorDavid_Corfield
• CommentTimeJul 11th 2012

Was that a coincidence you started this entry on the same day as I wrote this?

What David Ben-Zvi says above seems worth including. Something like

For any finite group the number of its conjugacy classes is equal to the number of its irreducible representations. For finite groups of Lie type this result can be strengthened to show that there is a canonical way to match conjugacy classes of a group $G$ to the irreducible representations of its Langlands dual $G'$.

• CommentRowNumber5.
• CommentAuthorUrs
• CommentTimeJul 11th 2012

seems worth including

Please do!

• CommentRowNumber6.
• CommentAuthorDavid_Corfield
• CommentTimeJul 11th 2012

OK, though I’m nervous about Ben-Zvi’s

I won’t give the precise statement but I think this is not a particularly misleading simplification

Anyway, doing that had me then create group of Lie type.

• CommentRowNumber7.
• CommentAuthorUrs
• CommentTimeJul 11th 2012

OK, though I’m nervous

Just add a corresponding disclaimer, making it clear that what you say is meant as a helpful guiding idea, not as a precise statement.

• CommentRowNumber8.
• CommentAuthorUrs
• CommentTimeJul 11th 2012

doing that had me then create group of Lie type.

Thanks. I have added a warning and links, and linked to it from group.

• CommentRowNumber9.
• CommentAuthorzskoda
• CommentTimeJul 11th 2012

Wikipedia is here useful, esp. for terminology: group of Lie type.

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