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created conjugacy class
I don’t have time to edit things now, but the example is wrong.
Sorry. Fixed. Thanks.
Was that a coincidence you started this entry on the same day as I wrote this?
What David Ben-Zvi says above seems worth including. Something like
For any finite group the number of its conjugacy classes is equal to the number of its irreducible representations. For finite groups of Lie type this result can be strengthened to show that there is a canonical way to match conjugacy classes of a group $G$ to the irreducible representations of its Langlands dual $G'$.
seems worth including
Please do!
OK, though I’m nervous about Ben-Zvi’s
I won’t give the precise statement but I think this is not a particularly misleading simplification
Anyway, doing that had me then create group of Lie type.
OK, though I’m nervous
Just add a corresponding disclaimer, making it clear that what you say is meant as a helpful guiding idea, not as a precise statement.
doing that had me then create group of Lie type.
Thanks. I have added a warning and links, and linked to it from group.
Wikipedia is here useful, esp. for terminology: group of Lie type.
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