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added a table with some homotopy groups in the unstable range to orthogonal group – Homotopy groups
Extended by two rows. SO(6) is the highest rank in which peculiar things happen below dimension 10. I think it would be good to extend it up to π11 or π12. Mimura and Mimura-Toda have this information for the last two rows. I’m looking around to see if I can find it for the other groups.
Ah, the venerable Encyclopedic Dictionary of Mathematics has a nice big table of these homotopy groups, for all the groups of interest. Also, the Abanov document has evaporated off the web.
Is there a way to see this online? In GoogleBooks somewhere?
Not that I’m aware of, which is a pity.
I’m sticking the table in, at least up to π12(SO(12)), since this probably covers all the orthogonal/homotopy groups of interest to string theory. I can do more if requested; the table goes up to π15(SO(17)).
In fact, in writing this out, it becomes clear that something different is going to happen for Ninebrane, since stably (SO(11) and beyond, hence in the right range for 11d supergravity) we have nontrivial torsion homotopy groups in dimension 8 and 9. SO(11) also has a nonstable ℤ/2 in π10, and its π11, though ℤ, is not in the stable range. Hmm
One can see a copy of the table in the EDM in page 970 of the Handbook of Algebraic Topology This chapter, number 19, was written by Mimura.
Thanks for expanding the table so much!
Yes, ninebrane structure is meant to kill just the fractional p3 of a Fivebrane structure, not the two ℤ/2ℤ-copies in between.
The way this appears in string theory is not actually that the structure group needs to be highly connected as such (that happens to be a byproduct), it’s that the polynomials in the pi appear as anomalies, and these need to be removed.
But how does one get the fractional p3? Does this exist even if the structure group doesn’t lift through those two copies?
There is a p3 on BFivebrane pulled back from BString and it will be a multiple of something. Do you mean how to pick the specific fraction?
The way I suggested to do it is just to let the process of higher Lie integration run. There is that L∞-cocycle μ12 on 𝔣𝔦𝔳𝔢𝔟𝔯𝔞𝔫𝔢 and just integrating that as in Cech Cocycles for Differential characteristic Classes (schreiber) gives some BNinebrane whose geometric realization is a candidate BNinebrane. I don’t know what the fraction comes out as, but the way the Lie integration works one is guaranteed that one kills a minimal element.
Ah, so the fact it’s a Lie algebra theoretic fact means you don’t see the ℤ/2? I worry though that in doing the Lie integration one needs to pick at some point a filler of some simplex. But let me remind myself how it works, first, before complaining it doesn’t! :-)
(reads…)
OK, I see. It’s just a formal thing, but one can then ’go down’ the Whitehead tower and construct the quotients by various to get the intermediate stages. The Lie integration just skips them altogether.
One point: under Lie integration#integrating_the_string_lie_2algebra_to_the_string_lie_2group there is what I think is a typo: D2*→D should probably by D2*→G, but I hesitate to change in case I’ve missed something.
Yes! Absolutely.
And yes, that should be a typo. If you have a second, please fix it. Myself I need to rush off..
Will do.
Fixed two errors in the table in the SO(6) row.
thanks. I wonder what happened there. Did I just make a misprint while copying? Probably.
@Urs, no it was probably me, since I added the citation for the SO(6) row via the exceptional isomorphism.
I have added to orthogonal group:
statement and proof that O(n)↪O(k) is an (n−1)-equivalence (here)
statement and proof that the Stiefel manifold Vn(k) is (n−1)-connected (here).
The latter I am also copying over to Stiefel manifold
I have now added the analogous statements with their analogous proofs also to unitary group.
Added more precise reference for the result that the induced map ℤ2=π3(SO(4))→π3(SO(5))=ℤ is (a,b)↦2a+b in
For reference, ℤ=π3(SO(3))→π3(SO(4))=ℤ2 is x↦(x,0). The same maps will work for the groups Spin(n) for n=3,4,5, which is what I care about.
I wanted this, so I could check what the map H4(BSp(2),ℤ)→H4(BSp(1)×BSp(1),ℤ) is.
Urs has been very careful with the isomorphism H4(BSpin(4),ℤ)→H4(BSp(1)×BSp(1),ℤ), making clear what the map ℤ2=H4(BSpin(4),ℤ)→H4(BSpin(3),ℤ)=ℤ should be, namely projection on the first factor. This agrees with the homotopy group computation, since we can use the isomorphisms π3(G)*≃π4(BG)*≃H4(BG,ℤ)*≃H4(BG,ℤ) for a simply-connected compact Lie group G.
However, it is less clear to me (and probably only because I haven’t thought about it hard enough) how to reconcile π3(Spin(4))→π3(Spin(5)), or equivalently, H4(BSpin(4),ℤ)→H4(BSpin(5),ℤ), with the explicit computation changing basis at Spin(4)#euler_class_and_pontryagin_class and the detail at Spin(5)#cohomology. The notation with the various references to 12p1 and 14p1 is obscuring things for me, so I don’t know how I should think of the map
H4(BSpin(5),ℤ)→H4(BSpin(4),ℤ)as written in this basis.
So I can see that the dual of H4(BSpin(4),ℤ)→H4(BSpin(5),ℤ), using the basis described by Tamura (chased through the isomorphisms) should be represented by the matrix
(21):ℤ=H4(BSpin(5),ℤ)→H4(BSpin(4),ℤ)≃H4(BSp(1)×BSp(1),ℤ)=ℤ2so at least on the first factor I get that we should have 12p1↦2⋅(14p1⊗1)—the notation is cute and makes sense. But I can’t see what’s going on with the second factor, yet. I mean, we could just have 12p1↦(1⊗14p1) (or equivalently, 12(χ+12p1)), and the fact this is not a stable class means that any notational niceties around p1 are probably not really relevant here.
The reason I’m thinking about this, is to try to understand better some of the deep detail of the big diagram from Twisted Cohomotopy implies twisted String structure on M5-branes, in particular the structure of the Sp(2)-equivariant quaternionic Hopf fibration, in its model as
(Sp(2)/Sp(1))//Sp(2)⟶(Sp(2)/(Sp(1)×Sp(1)))//Sp(2)No time right now and in the next days (this would have been good to discuss earlier!).
Just to note that 14p1 is an integral cohomology generator on BSpin(3), e.g. Lem. 2.1 in Čadek & Vanžura 1998 , which you probably have seen.
I think I may have figured it out. There’s a change of basis going on so the obvious basis for π3(Sp(1)×Sp(1)) is not what Tamura (following Steenrod’s book) is using. His first basis vector is (1,1) using the canonical product group structure, the second is (1,0). The first corresponds to the image of the generator of π3(Spin(3)) under the canonical Spin(3)→Spin(4). So using the obvious basis coming from π3(Sp(1)×Sp(1)), the map induced on π3 by Sp(1)×Sp(1)→Sp(2) really is the sum map. After changing basis, it gives the above result.
This is just a reminder for when editing functionality comes back, to write up a small explanation about the subtlety around the choice of bases as discussed in #19, #20 and #22.
Want to record another point: Tamura uses the basis (1,1),(1,0) relative to the obvious Künneth decomposition of H4 of Spin(4)≃Spin(3)×Spin(3) (which should be the same as the product structure coming from π3 of the same.
But Čadek & Vanžura use the basis (1,1),(0,1), as recorded by Urs, under the isomorphism just mentioned. This helps resolve my query in #20, where I was struggling with understanding the use of 1⊗14p1.
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