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Let K↪G be a normal subgroup. Then we have a quotient group G/K and a short exact sequence of groups 1→K→G→G/K→1. This sequence deloops giving the fiber sequence BK→BG→B(G/K). Is this also a cofiber sequence? I suspect so, but I’m not sure (for sure it is true for abelian groups). Yet the nLab page on cofiber sequences it seems this example is not discussed, so maybe I’m wrong here.
The reason I’m interested in BK→BG→B(G/K) being a cofiber sequence is that this would give a natural description of representations of the quotient G/K as representations of G together with the datum of a trivialization of their restriction to K (actually proving by hand this equivalence would be a proof that the sequence is a cofiber sequence, but if the result is already known (either as true or as false) I’d avoid working this out in detail myself).
I think it may not be. K→G is a crossed module, and G/K acts by outer automorphisms on K, and so at least in the topological classifying case sense, I think BG→B(G/K) is a fibre bundle with fibre BK and structure group Out(K). Or at least, something like that.
This is related somewhat to figuring out what the nonabelian version of a lifting bundle gerbe is.
Is it really true even for abelian groups if you’re talking about spaces rather than spectra?
Well, for central extensions, yes.
Unless I’m misinterpreting the notation, this seems like it would almost never happen just by inspection of cohomology groups. As a fiber sequence the relationship between the cohomology groups is a spectral sequence; in a cofiber sequence you get a long exact sequence.
Gah, I misread the question, so just ignore what I wrote in #2 and #4.
This is generally false. For example consider the central extension of abelian groups
ℤ→ℤ→ℤ/2after taking classifying spaces you get
S1→S1→ℝℙ∞but the cofiber of the first map (which is a double covering map) is only ℝℙ2.
I’ve added this counterexample to the page cofiber sequence.
Hi Chris,
Thanks, that’s a beautiful example!
By the way, the natural morphism cofiber(Bℤ→Bℤ)→B(ℤ/2) is homotopy equivalent the canonical inclusion ℝℝ2↪ℝℙ∞ in this case and so it induces in particular an isomorphism on fundamental groups up to π1. This I guess should be a general phenomenon, i.e., one should have cofiber(BK→BG)→B(G/K) inducing an iso on π0 and π1 in general (the π0 case being obvious, and the π1 being Seifert-van Kampen theorem), am I right?
Yes, that seems right to me.
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