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    • CommentRowNumber1.
    • CommentAuthorDavidRoberts
    • CommentTimeSep 4th 2014
    • (edited Sep 4th 2014)

    Given a locally connected topos Γ:ESet:Δ\Gamma\colon E \leftrightarrows Set : \Delta, we have the extra left adjoint π 0Δ\pi_0 \dashv \Delta. π 0\pi_0 preserves epis, as any left adjoint does. If EE is boolean I’m sure that π 0\pi_0 also reflects epis, at least assuming classical logic in the background. And I can’t think of a non-boolean example where π 0\pi_0 doesn’t reflect epis (just my own ignorance, rather than any compelling mathematical reason).

    Alternatively, I’m suspicious of π 0\pi_0 reflecting epis in the case of boolean EE without classical logic.

    To be concrete, say I’ve got an epi TVT \to V in boolean locally connected EE where VV is connected (throw in enough colimits if you like). TT has a component (as π 0(T)\pi_0(T) is inhabited assuming SetSet is constructively well-pointed), say T 0TT_0 \subset T. Then f:T 0Vf\colon T_0 \to V induces an iso on applying π 0\pi_0, but there’s no immediately compelling reason I can see for it to be epi. Given that EE is boolean, I can see that ff is not not epi, since if it were not epi, VV would not be connected since VV would split as the image of T 0T_0 and its complement.

    Presumably the topos of directed graphs would be good to consider. Hmmm…

    • CommentRowNumber2.
    • CommentAuthorDavidRoberts
    • CommentTimeSep 4th 2014

    In the last comment that should be reflexive directed graphs (see cohesive topos#Graphs, and indeed, π 0\pi_0 (there called Π 0\Pi_0) does not reflect epis.

    I’ve probably implicitly used the atomicity in the specific topos I have at hand :-S

    • CommentRowNumber3.
    • CommentAuthorZhen Lin
    • CommentTimeSep 4th 2014

    The topos of (reflexive directed) graphs is not boolean, though?

    • CommentRowNumber4.
    • CommentAuthorDavidRoberts
    • CommentTimeSep 4th 2014

    Yeah, but that addresses my first question as to a counterexample I was seeking.

    • CommentRowNumber5.
    • CommentAuthorZhen Lin
    • CommentTimeSep 4th 2014

    Returning the penultimate paragraph of #1, it seems you have assumed that π 0\pi_0 reflects initial objects. That is a weak form of Nullstellensatz, and I’m not sure it holds non-classically.

    Here’s the classical proof: take a subcanonical site for the topos consisting of connected objects, which we may do because it is locally connected; then constant presheaves are sheaves, so π 0\pi_0 can be computed as the colimit of the underlying presheaf and we are done.

    Of course, if you assume π 0\pi_0 reflects epimorphisms, then it also reflects initial objects: indeed, in a topos, any epimorphism whose codomain is an initial object must be an isomorphism.

    • CommentRowNumber6.
    • CommentAuthorDavidRoberts
    • CommentTimeSep 4th 2014

    Hmm, thanks. I’ve just taken π 0\pi_0 reflecting epis as a hypothesis now. It will hold in the final construction I do, so even if it is restrictive it makes the hypotheses cleaner.