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1. • CommentRowNumber1.
   • CommentAuthorUrs
   • CommentTimeOct 23rd 2017
   • PermaLink
   Author: Urs
   Format: MarkdownItexgave _[[Schwartz kernel theorem]]_ some minimal content

   gave Schwartz kernel theorem some minimal content

2. • CommentRowNumber2.
   • CommentAuthorUrs
   • CommentTimeOct 24th 2017
   • (edited Oct 24th 2017)
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   Author: Urs
   Format: MarkdownItexI am wondering now if we may lift the Schwartz kernel theorem to morphisms in $\mathbf{H} =$ [[smooth sets]] or in $\mathbf{H}$ the [[Cahier topos]], under the identification discussed at _[[distributions are the smooth linear functionals]]_. So conjecturally $\mathbb{R}$-linear morphisms in $\mathbf{H}$ of the form $$ \left[ \mathbb{R}^n, \mathbb{R} \right] \otimes_{\mathbb{R}} \left[ \mathbb{R}^n, \mathbb{R} \right] \longrightarrow \mathbb{R} $$ should be in linear bijection with $\mathbb{R}$-linear morphisms in $\mathbf{H}$ of the form $$ \mathbb{R}^n \times \mathbb{R}^n \longrightarrow \mathbb{R} $$ The would-be proof would first observe that by Cartesian closure the former are equivalent to $\mathbb{R}$-linear morphisms of the form $$ [\mathbb{R}^n, \mathbb{R}] \longrightarrow \left[ [\mathbb{R}^n, \mathbb{R}], \mathbb{R} \right]_{\mathbb{R}} \,. $$ Using on the right that [[distributions are the smooth linear functionals]] this is smooth functions from the space of smooth functions to that of compactly supported distributions. Now IF that identification would also apply here (i.e. where the codomain is not $\mathbb{R}$, but a space of distributions), we would conclude that this is the same as the continuous linear functions $$ \mathcal{E}(\mathbb{R}^n) \longrightarrow \mathcal{E}'(\mathbb{R}^n) $$ The [[Schwartz kernel theorem]] would then identify this with $\mathcal{E}'(\mathbb{R}^n \times \mathbb{R}^n)$ which, once more, is the same as $\mathbb{R}$-linear morphisms in $\mathbf{H}$ of the form. $$ \left[\mathbb{R}^n \times \mathbb{R}^n , \mathbb{R} \right] \longrightarrow \mathbb{R}^n \,. $$ Hence the question is: Does the proof of $$ \mathbf{H}\left( [\mathbb{R}^n, \mathbb{R}], \mathbb{R} \right)_{\mathbb{R}} \;\simeq\; \mathcal{E}'(\mathbb{R}^n) $$ generalize to yield $$ \mathbf{H}\left( [\mathbb{R}^n, \mathbb{R}],\,\, [[\mathbb{R}^n, \mathbb{R}],\mathbb{R}]_{\mathbb{R}} \right)_{\mathbb{R}} \;\simeq\; \mathcal{E}'(\mathbb{R}^n, \mathcal{E}'(\mathbb{R}^n)) $$ ??

   I am wondering now if we may lift the Schwartz kernel theorem to morphisms in smooth sets or in the Cahier topos, under the identification discussed at distributions are the smooth linear functionals.

   So conjecturally -linear morphisms in of the form

   should be in linear bijection with -linear morphisms in of the form

   The would-be proof would first observe that by Cartesian closure the former are equivalent to -linear morphisms of the form

   Using on the right that distributions are the smooth linear functionals this is smooth functions from the space of smooth functions to that of compactly supported distributions.

   Now IF that identification would also apply here (i.e. where the codomain is not , but a space of distributions), we would conclude that this is the same as the continuous linear functions

   The Schwartz kernel theorem would then identify this with which, once more, is the same as -linear morphisms in of the form.

   Hence the question is:

   Does the proof of

   generalize to yield

   ??