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• CommentRowNumber1.
• CommentAuthorUrs
• CommentTimeNov 30th 2017
• (edited Nov 30th 2017)

I have expanded the Idea section at state on a star-algebra and added a bunch of references.

The entry used to be called “state on an operator algebra”, but I renamed it (keeping the redirect) because part of the whole point of the definition is that it makes sense without necessarily having represented the “abstract” star-algebra as a C*-algebra of linear operators.

• CommentRowNumber2.
• CommentAuthorUrs
• CommentTimeDec 3rd 2017
• (edited Dec 3rd 2017)

added a little bit more to state on a star-algebra, cross-linked with pure state

• CommentRowNumber3.
• CommentAuthorUrs
• CommentTimeDec 11th 2017

Started an Examples-section (here) with making explicit the two archetypical examples (classical probability measure as state on measurable functions and element on Hilbert space as state on bounded operators).

• CommentRowNumber4.
• CommentAuthorUrs
• CommentTimeJan 20th 2020
• (edited Jan 20th 2020)

added a sentence at the very beginning, connecting back to quantum probability theory and AQFT

• CommentRowNumber5.
• CommentAuthorUrs
• CommentTimeMay 2nd 2021

• CommentRowNumber6.
• CommentAuthorUrs
• CommentTimeMay 7th 2021

• CommentRowNumber7.
• CommentAuthorUrs
• CommentTimeMay 7th 2021

Under “Properties – Closure properties” I added mentioning of convex combinations of states

and then I added (here) the “operator-state correspondence” (one way) saying that for $\rho \;\colon\; \mathcal{A} \to \mathbb{C}$ a state, with a non-null observable $O \in \mathcal{A}$, $\rho(O^\ast O) \neq 0$, then also

$\rho_O \;\colon\; A \;\mapsto\; \tfrac{1}{ \rho(O^\ast O) } \cdot \rho\big( O^\ast \cdot A \cdot O \big)$

is a state.

• CommentRowNumber8.
• CommentAuthorUrs
• CommentTimeMay 19th 2021

• CommentRowNumber9.
• CommentAuthorGuest
• CommentTimeSep 16th 2021
Hi,
I am confused about Proposition 3.1 where you say that L^1(Omega) is an algebra under pointwise operations, where $Omega$ is a probability space,
since the product of two integrable functions is not necessarily integrable (for example, the reciprocal of the square root of x, where Omega is the interval (0,1), multiplied by itself, is not integrable). I cannot see where I am wrong.
Fausto di Biase
fausto.dibiase@unich.it
• CommentRowNumber10.
• CommentAuthorUrs
• CommentTimeSep 16th 2021

Thanks for catching this, it was of course not stated correctly. I have now adjusted the wording (here, adding the previously missing condition that functions vanish at infinity) and have added a pointer to a textbook reference with more details.

This could certainly be expanded on further, but I leave it as is for the moment. If you feel like improving on it, please be invited to edit.