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This should have an entry of its own (as it does also on Wikipedia) for ease of linking with triality etc.
added pointer to
for discussion of the cohomology of
I was really looking for answer to the following question, but not sure yet:
What is the restriction of the Euler class on to , expressed in terms of the generators of ?
added statement of the cohomology ring of :
The ordinary cohomology ring of the classifying space is:
1) with coefficients in the cyclic group of order 2:
where are the universal Stiefel-Whitney classes,
and where
2) with coefficients in the integers:
where is the first fractional Pontryagin class, is the second Pontryagin class, is the Euler class.
Moreover, we have the relations
I have added pointer to
and added two of its Propositions to the text here, expanding on those distinct -subgroups of intersecting in .
Now I have a question: By that sequence of pulback squares we should get analogous distinct subgroup inclusions (in distinct conjugacy classes) of in and of in ?!
added pointers to
Robert Bryant, Remarks on Spinors in Low Dimension (pdf, BryantRemarksOnSpinorsInLowDimension.pdf:file)
Megan M. Kerr, New examples of homogeneous Einstein metrics, Michigan Math. J. Volume 45, Issue 1 (1998), 115-134 (euclid:1030132086)
also pointer to
I have added (here and here, respectively) the statements that
The three groups
,
,
with their canonical embeddings into represent three distinct conjugacy classes of subgroups of and triality permutes these three transitively;
The three groups
,
,
with their canonical embeddings into represent three distinct conjugacy classes of subgroups of and triality permutes these three transitively;
Hope I got this right. This is pretty subtle.
added statement of the action of triality on the universal characteristic classes, paraphrasing Čadek-Vanžura 97, Lemma 4.2:
Consider the delooping of the triality automorphism relating Sp(2).Sp(1) with Spin(5).Spin(3), from above, on classifying spaces
Then the pullback of the universal characteristic classes of (from above) along is as follows:
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