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    • CommentRowNumber1.
    • CommentAuthorUrs
    • CommentTimeMar 15th 2019
    • (edited Mar 15th 2019)

    Felix Wellen has been thinking about the following, maybe somebody has further thoughts:

    Currently an open problem is to get an intrinsic construction of differential cohesion, hence of the infinitesimal shape modality and/or the smooth real line in some analogy to how Mike’s real cohesion gets the shape modality from the topological real line constructed internally, in arXiv:1509.07584.

    But if we take the base topos of the cohesion to be the Boolean ¬¬\not \not-subtopos, so that

    ¬¬ \sharp \; \simeq \;\not \not

    (at least on 0-types?) then we may define infinitesimal disks to be the types 𝔻\mathbb{D} with

    𝔻* \sharp \mathbb{D} \simeq \ast

    (as in “logical topology”).

    Then one could try to define \Im as the localization at these 𝔻\mathbb{D}.

    But also, the infinitesimal disks should know about the smooth real line. For instance the Kock-Lawvere axioms gives that for the first order 1d disk 𝔻 1(1)\mathbb{D}^1(1) we have [𝔻 1(1),𝔻 1(1)] */[\mathbb{D}^1(1), \mathbb{D}^1(1)]^{\ast/} \simeq \mathbb{R} , with the correct smooth real line on the right.

    So the collection of the 𝔻\mathbb{D}-s, as above, should be enough to know the smooth 1\mathbb{R}^1, but I am not sure. If so, one could then declare the shape modality to be localization at this smooth 1\mathbb{R}^1.

    Maybe if all fits together, this construction could exhibit canonical differential cohesion.

    • CommentRowNumber2.
    • CommentAuthorMike Shulman
    • CommentTimeMar 15th 2019

    Interesting thought. Of course there are obstacles to overcome, e.g. it’s not clear that there are only a small number of such 𝔻\mathbb{D}, or how to identify one of them to call 𝔻 1(1)\mathbb{D}^1(1).

    • CommentRowNumber3.
    • CommentAuthorUrs
    • CommentTimeMar 15th 2019

    So Felix had this thought (if I may share this here) that the subobject of PropProp which is classified by Prop¬¬PropProp \overset{\not \not}{\longrightarrow} Prop should be something like the universal formal disk, and that \mathbb{R} should be the commutative part of its endomorphism ring. While I appreciate where he is headed, I don’t see through this yet.

    • CommentRowNumber4.
    • CommentAuthorMike Shulman
    • CommentTimeMar 17th 2019

    BTW, the equation =¬¬\sharp = \neg\neg only holds for (-1)-types (as it must, since ¬¬X\neg\neg X is always a (-1)-type while \sharp preserves nn-types for all nn). Also, I would expect that even in continuous \infty-groupoids, where there are no infinitesimals as such, there are still lots of (non-concrete) types XX with X=*\sharp X = \ast.

    • CommentRowNumber5.
    • CommentAuthorUrs
    • CommentTimeMar 17th 2019

    BTW, the equation =¬¬\sharp = \neg\neg only holds for (-1)-types (as it must, since ¬¬X\neg\neg X is always a (-1)-type while \sharp preserves nn-types for all nn).

    Thanks, of course. I was misled by thinking about subtoposes labeled J =J ¬¬J_\sharp = J_{\not \not}, but of course that just means that \sharp and ¬¬\not \not give the same Lawvere-Tierney operator.

    Still, I suppose it means we can define \sharp constructively in terms of ¬¬\not \not, right? And all \sharp corresponding to Boolean subtoposes should arise this way, I suppose.

    I would expect that even in continuous \infty-groupoids, where there are no infinitesimals as such, there are still lots of (non-concrete) types XX with X=*\sharp X = \ast.

    Hm, right. Maybe. Hm…

    • CommentRowNumber6.
    • CommentAuthorMike Shulman
    • CommentTimeMar 17th 2019

    I suppose it means we can define \sharp constructively in terms of ¬¬\not \not, right?

    Well, modulo hypercompletion. Assuming propositional resizing, we can nullify all the ¬¬\neg\neg-closed propositions to yield a topological subtopos of double-negation sheaves, and \sharp then coincides with this on all nn-types for finite nn (8.13 in BFP). It’s not immediately obvious that they coincide on untruncated types. But probably they do in the examples given that Gpd\infty Gpd is hypercomplete? I haven’t thought about this carefully.

    And all \sharp corresponding to Boolean subtoposes should arise this way, I suppose.

    Not all Boolean subtoposes are the double-negation sheaves, even in 1-topos theory. As a trivial case, the trivial subtopos is also Boolean.