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    • CommentRowNumber1.
    • CommentAuthorUrs
    • CommentTimeMar 22nd 2019

    in order to have a good place to record the diagram:

    (q1,q2)(xq1xˉq2)Sp(1)×Sp(1)Spin(4)Sp(1)Sp(1)SO(4)

    v1, current

    • CommentRowNumber2.
    • CommentAuthorUrs
    • CommentTimeApr 8th 2019
    • (edited Apr 8th 2019)

    just for completeness, I added this statement:


    The integral cohomology ring of the classifying space BSO(4) is

    H(p1,χ,W3)/(2W3)

    where

    • p1 is the first Pontryagin class

    • χ is the Euler class,

    • W3 is the integral Stiefel-Whitney class.

    Notice that the cup product of the Euler class with itself is the second Pontryagin class

    χχ=p2,

    which therefore, while present, does not appear as a separate generator.


    I hope I got this right that W5 does not appear.

    diff, v4, current

    • CommentRowNumber3.
    • CommentAuthorDavidRoberts
    • CommentTimeApr 8th 2019
    • (edited Apr 8th 2019)

    Yes, it seems to me that you only have W3 out of the integral SW classes, based on one of those sources I sent you.

    • CommentRowNumber4.
    • CommentAuthorUrs
    • CommentTimeJun 5th 2019

    copied over the homotopy groups of SO(4) in low degree

    G π1 π2 π3 π4 π5 π6 π7 π8 π9 π10 π11 π12 π13 π14 π15
    SO(4) 2 0 2 22 22 212 22 22 23 215 22 42 22212 42284 42

    diff, v7, current