John, I fixed the glitch at general linear group, and I’ve read through the queries at Schur functor, which I’ll answer when I get a suitable moment. I’m having fun with that!
]]>I’m sure you’re right, Todd - I just want someone to step in and lay claim to the title of ’someone who knows algebraic geometry’ by correcting that darn mistake. I’m too busy doing other stuff.
(Read my queries on the Schur functor page!)
]]>I think so. I guess it was easier than I thought!
]]>Isn’t it just an affine scheme given by the commutative ring ? Am I making a stupid mistake?
]]>Alright, the actual group scheme is , which is the functor of points sending each commutative ring to the group of invertible matrices over that ring.
is secretly notation for , which is the fibre of over .
Actually proving it’s a scheme requires actually knowing something about algebraic geometry (although it probably isn’t very hard. I think Toen gives a proof of the special case for ), however, so I’ll take my leave.
]]>Yes, as a variety you could define it by the equation where is an extra indeterminate you throw in.
]]>I added material to Young diagram, which forced me to create entries for special linear group and special unitary group. I also added a slight clarification to unitary group.
I would love it if someone who knows algebraic geometry would fix this remark at general linear group:
Given a commutative field , the general linear group (or ) is the group of invertible matrices with entries in . It can be considered as a subvariety of the affine space of square matrices of size carved out by the equations saying that the determinant of a matrix is zero.
In fact it’s ’carved out’ by the inequality saying the determinant is not zero… so its description as an algebraic variety is somewhat different than suggested above. Right???
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