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nLab > Latest Changes: exponentiable functor

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  1.  
    • CommentRowNumber1.
    • CommentAuthorJohn Baez
    • CommentTimeSep 13th 2022

    I added the word “strict” here:

    The theorem is then that the following are equivalent:

    because strict and weak Conduché functors are being distinguished in this article.

    diff, v24, current

    • CommentRowNumber2.
    • CommentAuthormattecapu
    • CommentTimeJan 19th 2023

    Redirects wrong accent

    diff, v26, current

    • CommentRowNumber3.
    • CommentAuthorvarkor
    • CommentTimeJan 19th 2023

    I don’t believe we usually add redirects for typos.

    • CommentRowNumber4.
    • CommentAuthorGnampfissimo
    • CommentTimeMay 22nd 2023

    Redirects wrong accent

    diff, v27, current

  5. Added new material on double categories from a paper by Grandis and Pare, the Conduche condition appears in the definition of completeness for a double category.

    Patrick Nicodemus

    diff, v28, current

    • CommentRowNumber6.
    • CommentAuthorvarkor
    • CommentTimeDec 29th 2023

    Would anyone object to renaming this page to “exponentiable functor” (which is one of the other terms mentioned on the page)? Although Conduché functor is used in the literature, “exponentiable functor” is more descriptive, and Conduché was not the first to consider such functors.

    • CommentRowNumber7.
    • CommentAuthorvarkor
    • CommentTimeDec 29th 2023

    Mentioned discrete Conduché functors.

    diff, v29, current

    • CommentRowNumber8.
    • CommentAuthorSiyaM
    • CommentTimeJul 29th 2024
    I am a first year PhD student. Recently been interested in double fibrations, also Conduche fibrations, I am trying to prove the above mentioned theorem and I have been struggling. I would like to ask if there are such analogues (of Conduche fibrations) in double categories?
    • CommentRowNumber9.
    • CommentAuthorvarkor
    • CommentTimeJul 29th 2024

    Fixed reference to Johnstone’s paper, which does not contain a complete proof of the stated theorem.

    diff, v30, current

    • CommentRowNumber10.
    • CommentAuthorvarkor
    • CommentTimeJul 29th 2024

    Renamed page to exponentiable functor, following no objections; the concept is not due to Conduché.

    diff, v30, current

    • CommentRowNumber11.
    • CommentAuthorvarkor
    • CommentTimeJul 29th 2024

    Added terminology “ULF”.

    diff, v32, current

    • CommentRowNumber12.
    • CommentAuthorSiyaM
    • CommentTimeAug 9th 2024
    Is there an alternative proof (perhaps much simpler) for showing that a functor is exponentiable in Cat iff it is a Conduche fibration? I have managed to work through Johnstone's proof for the sufficient condition. However, Street does provide a proof but much more complicated in a sense that he uses coend calculus and monadic functors.

1 to 12 of 12

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