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1. • CommentRowNumber1.
   • CommentAuthorUrs
   • CommentTimeMar 28th 2011
   • PermaLink
   Author: Urs
   Format: MarkdownItexhave created [[super L-infinity algebra]]

   have created super L-infinity algebra

2. • CommentRowNumber2.
   • CommentAuthorjim_stasheff
   • CommentTimeMar 29th 2011
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   Author: jim_stasheff
   Format: TextI assume super = Z_2 graded in addition to the grading implicit in Linfty Everything would go through if the additional grading were over Z?

   I assume super = Z_2 graded in addition to the grading implicit in Linfty
   Everything would go through if the additional grading were over Z?
3. • CommentRowNumber3.
   • CommentAuthorUrs
   • CommentTimeMar 29th 2011
   • PermaLink
   Author: Urs
   Format: MarkdownItex> I assume super = Z_2 graded in addition to the grading implicit in Linfty Yes. > Everything would go through if the additional grading were over Z? Yes, then we should speak of a $\mathbb{Z}_2$-graded $L_\infty$ algebra.

   I assume super = Z_2 graded in addition to the grading implicit in Linfty

   Yes.

   Everything would go through if the additional grading were over Z?

   Yes, then we should speak of a $\mathbb{Z}_2$-graded $L_\infty$ algebra.