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    • CommentRowNumber1.
    • CommentAuthorHarry Gindi
    • CommentTimeOct 18th 2011

    Let P be the strict omega-category generated as follows:

    Let A_0=∂O^1, and let E_n=Hom(∂O^n,A_{n-1}), where A_n is obtained by the cocartesian square:

    E_n × ∂O^n -> A_{n-1}
    |                        |
    |                        |
    v                        v
    E_n × O^n —-> A_n

    This gives an inductive system A_0 -> A_1 -> … -> A_n ->…

    And we call the inductive limit of this system P.

    Then P gives a factorization of ∂O^1->O^0 into a natural cofibration followed by a natural trivial fibration.

    Recall that the Crans-Gray tensor product is a biclosed monoidal structure on str-ω-cat induced by the Day convolution product on the category of cubical sets extending the canonical product of cubes i× j= i+j\Box_i \times \Box_j=\Box_{i+j} inherited from the category of sets.

    Recall that in a monoidal category (V,,I,,r)(V,\otimes, I, \ell, r) (here, :IXX\ell:I\otimes X \cong X and r:XIXr:X\otimes I \cong X are the natural isomorphisms for the unity object), an object X is called quasi-central in V if there exists a natural isomorphism α:XX\alpha: X\otimes - \to - \otimes X such that for any objects A and B in V, the following coherence conditions are satisfied:

    α AB=(1 Aα B)(α A1 B\alpha_{A\otimes B}=(1_{A} \otimes \alpha_B)(\alpha_A \otimes 1_B

    and

    α I= X 1r X\alpha_{I}=\ell^{-1}_X r_X

    Then my question: Is the object P defined as above quasicentral in the Crans-Gray monoidal category of strict ω-categories?

    If not, can it at least be shown that it is quasicentral in the monoidal subcategory of cofibrant objects?

    The intuition here is that it seems like for any fixed arbitrary strict ω\omega-category CC and any cofibrant object AA, you can manufacture a natural bijection

    Hom(PA,C)Hom(P,RHom(A,C))Hom(P,LHom(A,C))Hom(AP,C)Hom(P\otimes A, C)\cong Hom(P,RHom(A,C))\cong Hom(P,LHom(A,C)) \cong Hom(A\otimes P,C)

    since a P-shaped left-lax transfor seems like it can be reversed to a P-shaped right-lax transfor by composing with a fixed automorphism of P (since P classifies equivalences).

    • CommentRowNumber2.
    • CommentAuthorHarry Gindi
    • CommentTimeOct 19th 2011

    Uhh…

    Can you do something silly like this:

    A map PD nXP\otimes D_n\to X corresponds by adjunction to a map D nLHom(P,X)D_n\to LHom(P,X), but there exists a natural isomorphism PP opP\to P^{op}, so we can compose D nLHom(P op,X)D_n\to LHom(P^{op},X), but then by duality, this corresponds to a map D nLHom(P,X op).D_n\to LHom(P,X^{op}). Passing back along the adjoint, we obtain a map PD nX opP\otimes D_n \to X^{op}, which gives, by duality, a map (PD n) opX(P\otimes D_n)^{op}\to X, but due to the interaction of duality with the tensor product, this gives us a map D n opP opXD_n^{op}\otimes P^{op} \to X. Then precomposing with the isomorphism D nPD n opP opD_n\otimes P \to D_n^{op} \otimes P^{op}, this gives a map D nPXD_n\otimes P \to X.

    Obviously, we can do this in reverse, so we see that we have commutativity of PP with the n-globes and their boundaries… if I didn’t screw up!