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    • CommentRowNumber1.
    • CommentAuthorUrs
    • CommentTimeDec 7th 2013

    I am feeling a bit silly about the following, as this is probably easy and I must be being dense, but I’ll throw this out as a question now anyway:

    given an \infty-functor f:XYf : X \longrightarrow Y between \infty-groupoids, we get an induced pullback

    f *:EMod(Y)EMod(X) f^\ast : E Mod(Y) \longrightarrow E Mod(X)

    for EE any E E_\infty-ring and EMod()Func(,EMod)E Mod(-) \coloneqq Func(-, E Mod) the \infty-category of EE-\infty-modules on XX.

    This f *f^\ast should be closed monoidal, I suppose. I can see a pseudo-proof, but I am a bit stuck with making it a rigorous proof. Can anyone help?

    • CommentRowNumber2.
    • CommentAuthorUrs
    • CommentTimeDec 7th 2013
    • (edited Dec 7th 2013)

    Ah, I realize that I am looking here exactly for the \infty-version of Mike’s article

    The context is example 2.2 there, with V\mathbf{V} now the \infty-category EModE Mod, and I am after the \infty-analog of the consequence example 2.17 of theorem 2.14 there.

    With a minimum of enriched \infty-category theory all this should just go through verbatim…