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    • CommentRowNumber1.
    • CommentAuthorporton
    • CommentTimeDec 23rd 2014
    • (edited Dec 23rd 2014)

    It seems that I’ve proved that every atomistic poset is a co-brouwerian lattice.

    The proof is an easy generalization of my theorem 6.86 in my draft book:

    My book draft

    Is it true? (in other words, there is no error in my proof?)

    Please confirm the correctness of my result before we edit and include this result into nLab article

    Should we also edit Wikipedia to include this fact? (If yes, which reference to cite?)

    • CommentRowNumber2.
    • CommentAuthorTodd_Trimble
    • CommentTimeDec 23rd 2014

    It’s not true. For example, a typical geometric lattice such as the lattice of equivalence relations on a finite set is not even distributive, much less co-brouwerian (meaning, I presume, opposite to a Heyting algebra).

    • CommentRowNumber3.
    • CommentAuthorporton
    • CommentTimeDec 23rd 2014

    Oh, I see. My proof uses features specific to funcoids and does not generalize for other atomistic lattices.

    Sorry for your time spend about a non-existent generalization of my proof. (The proof itself is correct, just it cannot be generalized.)