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1. • CommentRowNumber1.
   • CommentAuthorTobyBartels
   • CommentTimeJul 2nd 2010
   • PermaLink
   Author: TobyBartels
   Format: MarkdownItex[[dense subspace]], [[double negation]], [[bicartesian category]]

   dense subspace, double negation, bicartesian category

2. • CommentRowNumber2.
   • CommentAuthorTobyBartels
   • CommentTimeJul 3rd 2010
   • PermaLink
   Author: TobyBartels
   Format: MarkdownItexAlso [[embedding]], quite a stub.

   Also embedding, quite a stub.

3. • CommentRowNumber3.
   • CommentAuthorTobyBartels
   • CommentTimeJul 3rd 2010
   • PermaLink
   Author: TobyBartels
   Format: MarkdownItexAnd [[inclusion function]].

   And inclusion function.

4. • CommentRowNumber4.
   • CommentAuthorMike Shulman
   • CommentTimeJul 9th 2010
   • PermaLink
   Author: Mike Shulman
   Format: MarkdownItexI responded to the query box at [[bicartesian closed category]] by creating [[cocartesian closed category]].

   I responded to the query box at bicartesian closed category by creating cocartesian closed category.

5. • CommentRowNumber5.
   • CommentAuthorUrs
   • CommentTimeJul 9th 2010
   • PermaLink
   Author: Urs
   Format: MarkdownItexconcerning the sentence at [[embedding]] that we "need to be able to interpret $f$ as a morphism to $im f$": What is guaranteed, by definition of image, is the factorization $f : X \stackrel{\tilde f}{\to} im f \hookrightarrow Y$, whrere the second morphism is a mono. It feels like we should be saying that $f$ is an embedding if $\tilde f$ is an iso.

   concerning the sentence at embedding that we “need to be able to interpret $f$ as a morphism to $im f$”:

   What is guaranteed, by definition of image, is the factorization $f : X \stackrel{\tilde f}{\to} im f \hookrightarrow Y$, whrere the second morphism is a mono.

   It feels like we should be saying that $f$ is an embedding if $\tilde f$ is an iso.

6. • CommentRowNumber6.
   • CommentAuthorTobyBartels
   • CommentTimeJul 9th 2010
   • PermaLink
   Author: TobyBartels
   Format: MarkdownItex@ Urs Yes, that makes sense.

   @ Urs

   Yes, that makes sense.