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    • CommentRowNumber1.
    • CommentAuthorZhen Huan
    • CommentTimeOct 5th 2024

    I have a maybe basic question but I cannot figure it out. We know on the free loop space LX of a smooth manifold X, there is a circle action induced by the rotation. If we consider any an (∞,1)-category C with (∞,1)-pullbacks instead of the category of smooth manifolds, we can define the free loop space object, as we can see here https://ncatlab.org/nlab/show/free+loop+space+object#CircleAction Can we still have a higher “rotation” on a free loop object? I don’t think the intrinsic circle action on that page is equivalent to “rotation”. Thanks.

    • CommentRowNumber2.
    • CommentAuthorUrs
    • CommentTimeOct 5th 2024
    • (edited Oct 5th 2024)

    This is the issue of passing from

    • the circle S 1S^1 regarded as a Lie group and as such as a smooth group \infty-stack which is 0-truncated but not geometrically discrete

    to

    • its “shape” ʃS 1ʃ S^1 which is equivalently the “simplicial circle” and as such a smooth group \infty-stack which is 1-truncated but geometrically discrete.

    The shape unit map

    η S 1:S 1ʃS 1 \eta_{S^1} : S^1 \mapsto ʃ S^1

    respects these \infty-group structures and hence records what becomes of the “naive” S 1S^1 action by rotation as one passes to homotopy types and is left “only” with the higher group action of ʃS 1ʃ S^1.

    The relation between

    • the free loop space of the form Map(S 1,())Map(S^1, (-)), with its naive action by circle rotation

    to

    • the free loop space Map(ʃS 1,ʃ())Map(ʃ S^1, ʃ (-)), with only a homotopy-action by ʃS 1ʃ S^1 left

    is to a large part the topic of that article “Cyclification of Orbifolds”, beginning p. 13.

    • CommentRowNumber3.
    • CommentAuthorZhen Huan
    • CommentTimeOct 5th 2024

    Thanks! Zhen