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    • CommentRowNumber1.
    • CommentAuthorTobyBartels
    • CommentTimeFeb 20th 2013

    I made a stub uniform convergence space, but I need to read the reference.

    • CommentRowNumber2.
    • CommentAuthorTobyBartels
    • CommentTimeFeb 22nd 2013

    We now have motivation (made up by me) but not yet a definition.

    • CommentRowNumber3.
    • CommentAuthorTobyBartels
    • CommentTimeFeb 22nd 2013

    Related edits to Cauchy space, Cauchy filter, and ultrafilter.

    • CommentRowNumber4.
    • CommentAuthorTobyBartels
    • CommentTimeFeb 22nd 2013

    Now with a definition at uniform convergence space.

    • CommentRowNumber5.
    • CommentAuthorTobyBartels
    • CommentTimeFeb 22nd 2013

    A mistake in the nonstandard stuff at Cauchy filter. Fixed.

    • CommentRowNumber6.
    • CommentAuthorTobyBartels
    • CommentTimeFeb 24th 2013

    Now probably everything that I'll write at uniform convergence space is pretty much there.

    • CommentRowNumber7.
    • CommentAuthorMike Shulman
    • CommentTimeFeb 26th 2013

    Nice! The idea of a “filter of filters” takes some wrapping my head around, though.

    • CommentRowNumber8.
    • CommentAuthorTobyBartels
    • CommentTimeFeb 26th 2013

    Yeah, I have to keep reminding myself that this isn't really more abstract than a Cauchy space, or go back to the example of a metric space, where a uniform filter may be assumed to be (a superset of the eventuality filter of the pairing of) a pair of sequences.

    • CommentRowNumber9.
    • CommentAuthorTobyBartels
    • CommentTimeMay 26th 2013

    I changed the ad-hoc term “uniform filter” to “asymptotic filter”, although this is wrong. There must be some term for a pair of sequences a,ba, b such that lim n(a nb n)=0\lim_n (a_n - b_n) = 0, but what is it? I know “coterminal”, but this assumes that they converge; and “asymptotic” really means that lim na n/b n=1\lim_n a_n/b_n = 1 (at least for positive-valued sequences), which is weaker.

    • CommentRowNumber10.
    • CommentAuthorDavidRoberts
    • CommentTimeMay 26th 2013

    Additively asymptotic?

    • CommentRowNumber11.
    • CommentAuthorTobyBartels
    • CommentTimeMay 26th 2013

    I thought of ‘exponentially asymptotic’, since expaexpb\exp a \sim \exp b. But why doesn't it have its own term? It's a very natural notion.

    • CommentRowNumber12.
    • CommentAuthorTobyBartels
    • CommentTimeJul 2nd 2013

    Based on the answers (or lack thereof) at my MathOverflow question, I’m going to stick with ‘asymptotic’, but I added to the terminological warning.

    • CommentRowNumber13.
    • CommentAuthorTim_Porter
    • CommentTimeJul 3rd 2013

    @Toby: as support for that terminology look at asymptotic C-star-homomorphism. This notion, due to Connes and Higson, corresponds in the (non-commutative) C*-algebra setting to strong shape morphisms in the corresponding topological one.