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    • CommentRowNumber1.
    • CommentAuthorDavid_Corfield
    • CommentTimeMar 4th 2017

    It occurred to me that HoTT should have something to say about anafunctors, if only to say they’re already built in, or something like that. But I can’t see the two terms appearing together anywhere (no ’anafuntor’ in the HoTT book, no ’type’ in anafunctor) except in this blog post:

    To work in category theory based on set theory and classical logic, while avoiding AC, one is therefore justified in “mixing and matching” functors and anafunctors as convenient, but discussing them all as if they were regular functors (except when defining a particular anafunctor). Such usage can be formalized by turning everything into an anafunctor, and translating functor operations and properties into corresponding operations and properties of anafunctors.

    there is a better solution, which is to throw out set theory as a foundation of category theory and start over with homotopy type theory. In that case, thanks to a generalized notion of equality, regular functors act like anafunctors, and in particular AP holds.

    This AP is

    “Axiom of Protoequivalence”—that is, the statement that every fully faithful, essentially surjective functor (i.e. every protoequivalence) is an equivalance

    I can’t see that the blogger got round to starting over with HoTT.

    So my question is whether something useful could be added to anafunctor even if it’s only to say that HoTT renders it unnecessary, or whatever it does?

    • CommentRowNumber2.
    • CommentAuthormaxsnew
    • CommentTimeMar 4th 2017
    • (edited Mar 4th 2017)

    I can’t see that the blogger got round to starting over with HoTT.

    It is discussed more in his PhD thesis: https://github.com/byorgey/thesis/raw/master/Yorgey-thesis-final-2014-11-17.pdf

    Though surely there is more to say.

    • CommentRowNumber3.
    • CommentAuthorMike Shulman
    • CommentTimeMar 5th 2017

    If you know what an anafunctor is, then on reading chapter 9 of the book carefully you may detect their ghostly presence. (-: The short answer is that anafunctors are unnecessary when using “saturated/univalent” categories in HoTT, because of their “functor comprehension principle”. An anafunctor is a span whose first leg is a surjective and fully faithful functor, but for saturated categories any such functor is an equivalence (in the strong sense of having an inverse), so any anafunctor is equivalent to a functor.

    • CommentRowNumber4.
    • CommentAuthorDavid_Corfield
    • CommentTimeMar 5th 2017
    • (edited Mar 5th 2017)

    I extracted #3 in a new section, although perhaps it should come earlier. There are terms to explain there. Is the ’saturated’ the same as in saturated class of maps or saturated class of limits? There’s also ’saturated homotopical category’ at relative category. By the way, none of these last three pages mentions each other.

    • CommentRowNumber5.
    • CommentAuthorDavidRoberts
    • CommentTimeMar 5th 2017

    Saturated/univalent would be something like ’projective’. The functor pointing the wrong in an anafunctor is an acyclic fibration (in the canonical model structure), and having its codomain saturated guarantees a splitting.

    • CommentRowNumber6.
    • CommentAuthorMike Shulman
    • CommentTimeMar 5th 2017

    No, no relation to other kinds of saturation. Also it’s not projectivity but more like injectivity; it’s not univalence of the domain of an anafunctor that makes it a functor but rather the codomain. See theorem 9.9.4 in the HoTT book: univalent categories are local with respect to weak equivalences.

    • CommentRowNumber7.
    • CommentAuthorDavid_Corfield
    • CommentTimeMar 5th 2017

    I put in a reference to def 9.1.3, as the notes to chap. 9 suggest.

    • CommentRowNumber8.
    • CommentAuthorDavidRoberts
    • CommentTimeMar 5th 2017

    @Mike

    Then I don’t understand what you mean by this sentence :

    An anafunctor is a span whose first leg is a surjective and fully faithful functor, but for saturated categories any such functor is an equivalence (in the strong sense of having an inverse)

    Since you haven’t referred to the codomain of the anafunctor here at all, merely the ’domain half’. Did you mean for CDC\to D ff and surjective on objects that DD saturated or CC saturated this becomes a legit equivalence?

    • CommentRowNumber9.
    • CommentAuthorMike Shulman
    • CommentTimeMar 6th 2017

    Yes, I think C saturated suffices, but C and D both saturated certainly suffices. By “for saturated categories” I meant “if all categories in sight are saturated”.